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От: | ADVer | |
| Дата: | 14.04.09 08:26 | ||
| Оценка: | |||
перебрать элементы в xml через xsl , но не используя for-each
HS><?xml version="1.0" encoding="WINDOWS-1251"?>
HS><?xml-stylesheet type='text/xsl' href='dogs.xsl'?>
HS><tutorial>
HS><enimals>
HS> <dogs>
HS> <dogsCaption>Собаки</dogsCaption>
HS> <dogsCaptionName>Порода</dogsCaptionName>
HS> <dogsCaptionWeight>Вес</dogsCaptionWeight>
HS> <dogsCaptionColor>Цвет</dogsCaptionColor>
HS> <dog>
HS> <dogName>Дог</dogName>
HS> <dogWeight caption="кг">35</dogWeight>
HS> <dogColor>серый</dogColor>
HS> </dog>
HS> <dog>
HS> <dogName>Овчарка</dogName>
HS> <dogWeight caption="кг">25</dogWeight>
HS> <dogColor>чёрная</dogColor>
HS> </dog>
HS> <dog>
HS> <dogName>Пудель</dogName>
HS> <dogWeight caption="кг">15</dogWeight>
HS> <dogColor>белый</dogColor>
HS> </dog>
HS> </dogs>
HS></enimals>
HS></tutorial>
HS>HS><xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/TR/WD-xsl">
HS><xsl:template match="/">
HS><table border="1">
HS> <tr bgcolor="#CCCCCC">
HS> <td align="center"><strong><xsl:value-of select="//dogsCaptionName"/></strong></td>
HS> <td align="center"><strong><xsl:value-of select="//dogsCaptionWeight"/></strong></td>
HS> <td align="center"><strong><xsl:value-of select="//dogsCaptionColor"/></strong></td>
HS> </tr>
HS> <xsl:for-each select="tutorial/enimals/dogs/dog">
HS> <tr bgcolor="#F5F5F5">
HS> <td><xsl:value-of select="dogName"/></td>
HS> <td align="right"><xsl:value-of select="dogWeight"/> <xsl:value-of select="dogWeight/@caption"/></td>
HS> <td><xsl:value-of select="dogColor"/></td>
HS> </tr>
HS> </xsl:for-each>
HS></table>
HS></xsl:template>
HS></xsl:stylesheet>
HS>